Question

Phương trình có nghiệm là

Answer 1

\(\dfrac{x+31}{5}+\dfrac{x-12}{48}+\dfrac{x+4}{32}=-3\)

\(\Rightarrow\left(\dfrac{x+31}{5}+1\right)+\left(\dfrac{x-12}{48}+1\right)+\left(\dfrac{x+4}{32}+1\right)=0\)

\(\Rightarrow\dfrac{x+36}{5}+\dfrac{x+36}{48}+\dfrac{x+36}{32}=0\)

\(\Rightarrow\left(x+36\right)\left(\dfrac{1}{5}+\dfrac{1}{48}+\dfrac{1}{32}\right)=0\)

Mà \(\dfrac{1}{5}+\dfrac{1}{48}+\dfrac{1}{32}\ne0\)

\(\Rightarrow x+36=0\)

\(\Rightarrow x=-36\)

Vậy x = -36

Answer 2

x = -36