a) \(x^2+5x-6=x^2+x-6x-6=x\left(x+1\right)-6\left(x+1\right)=\left(x+1\right)\left(x-6\right)\)
b) \(x^3-x+3x^2y+3xy^2+y^3-y\)
\(=\left(x^3+3x^2y+3xy^2+y^2\right)-\left(x+y\right)\)
\(=\left(x+y\right)^3-\left(x+y\right)\)
\(=\left(x+y\right)\left[\left(x+y\right)^2-1\right]=\left(x+y\right)\left(x+y+1\right)\left(x+y-1\right)\)
a) a) x2 + 5x - 6=(x2-x)+(6x-6)= x(x-1)+6(x-1)=(x+6)(x-1)
a)x2+5x-6
Ta có:x2+6x-x-6=x2-x+6x-6=x.(x-1)+6.(x-1)=(x-1)(x+6)
MK mới học lớp 7 thôi nên chỉ làm câu a
b)x3-x+3x2y+3xy2+y3-y
=(x3+3x2y+3xy2+y3)-x-y
=(x+y)3-(x+y)
=(x+y).(x+y-1)(x+y+1)