Question

Phân tích thành nhân tử

a) x² - 9

b) 4x² -25

c) x⁶ - y⁶

Answer 1

a, \(x^2-9=\left(x-3\right)\left(x+3\right)\)

b, \(4x^2-25=\left(2x-5\right)\left(2x+5\right)\)

c, \(x^6-y^6=\left(x^3-y^3\right)\left(x^3+y^3\right)\)

Answer 2

\(c.x^6-y^6=\left(x^3+y^3\right)\left(x^3-y^3\right)\\ =\left(x+y\right)\left(x^2-xy+y^2\right)\left(x-y\right)\left(x^2+xy+y^2\right)\)