Question

Phân tích thành nhân tử :

a) 3x² + 6xy + 3y² - 3z²

b) x² - 2xy + y² - z² + 2zt - t²

Answer 1

a) \(=3\left(x^2+2xy+y^2-z^2\right)\)

b) \(=\left(x^2-2xy+y^2\right)-\left(z^2-2zt+t^2\right)=\left(x-y\right)^2-\left(z-t\right)^2=\left(x-y-z+t\right)\left(x-y+z-t\right)\)

Ko chắc nha

Answer 2

\(a,3x^2+6xy+3y^2-3z^2\)

\(=3\left(x^2+2xy+y^2-x^2\right)\)

\(=3\left[\left(x+y\right)^2-z^2\right]=3\left(x+y-z\right)\left(x+y+z\right)\)