Question

Phân tích đa thức thành nhân tử"

\(x^3-2x-4\) \(x^2+4x+3\)

Answer 1

a, \(x^3-2x-4\) b, \(x^2+4x+3\) nhá

 

Answer 2

Nghịch xíu :v

a, \(x^3-2x-4\)

\(=x^3-2x^2+2x^2-4x+2x-4\)

\(=x^2\left(x-2\right)-2x\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-2x+2\right)\)

b, \(x^2+4x+3\)

\(=x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)\)

\(=\left(x+1\right)\left(x+3\right)\)

Chúc bạn học tốt!!!

Answer 3

a) \(x^3-2x-4=x^3+2x^2+2x-2x^2-4x-4\)

\(=x\left(x^2+2x+2\right)-2\left(x^2+2x+2\right)=\left(x-2\right)\left(x^2+2x+2\right)\)

b) \(x^2+4x+3=x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)\)

\(\left(x+3\right)\left(x+1\right)\)