x2 + y2 - x2y2 + xy - x - y
=(x2-x2y2)+(y2-y)+(xy-x)
=x2(1-y)(1+y)-y(1-y)-x(1-y)
=(1-y)(x2+x2y-x-y)
=(1-y)[(x2-y)+(x2-x)]
=(1-y)[y(x-1)(x+1)+x(x-1)]
=(1-y)(x-1)(xy+x+y)
Đúng 0
Bình luận (0)