Question

phân tích đa thức thành nhân tử

x^3-3x^2+2

Answer 1

Ta có:\(x^3-3x^2+2\)

\(=x^3-x^2-2x^2+2\)

\(=\left(x^3-x^2\right)-\left(2x^2-2\right)\)

\(=x^2\left(x-1\right)-2\left(x^2-1\right)\)

\(=x^2\left(x-1\right)-2\left(x-1\right)\left(x+1\right)\)

\(=\left(x-1\right)\left[x^2-2.\left(x+1\right)\right]\)

\(=\left(x-1\right)\left(x^2-2x-2\right)\)

chúc bạn hok tốt !!!

Answer 2

\(x^3-3x^2+2\)

=\(x^3-x^2-2x^2+2\)

=[\(x^3-x^2\)]-[\(2x^2-2\)]

=\(x^2\)[x-1] - 2[x-1]

=[x-1][\(x^2-2\)]