Question

Phân tích đa thức thành nhân tử bằng phương pháp bổ sung hằng đẳng thức

\(3x^2+x-2\)

Answer 1

\(3x^2+x-2\)

=\(3x^2+3x-2x-2\)

=\(3x\left(x+1\right)-2\left(x+1\right)\)

=\(\left(3x-2\right)\left(x+1\right)\)

Answer 2

3x²+x-2

=3x²+3x-3x+x-2

=3x²+3x-2x-2

=3x.(x+1)-2(x+1)

=(x+1).(3x-2)

Answer 3

"₫e bai" ghi ro pp, hdt. "

...

A=3x^2 +x-2

12A=36x^2+12x-24

12A=(6x)^2 +2.(6x)+1-25

=(6x+1)^2-5^2

=(6x+1-5)(6x+1+5)

=2.6.(3x-2)(x+1)

A=(3x-2)(x+1)

Answer 4

\(3x^2\)+x-2

=\(3x^2\)+3x-3x+x-2

=\(3x^2\)+3x-2x-2

=3x.(x+1)-2(x+1)

=(x+1).(3x-2)