Question

phân tích đa thức thành nhân tử :

\(x^2.\left(x^4-1\right).\left(x^2+2\right)+1\)

Answer 1

\(x^2.\left(x^4-1\right).\left(x^2+2\right)+1=\left(x^6-x^2\right)\left(x^2+2\right)+1\)

\(=x^8-x^4+2x^6-2x^2+1\)

\(=2x^2\left(\dfrac{1}{2}.x^6-\dfrac{1}{2}x^2+x^4-1+1\right)\)

\(=2x^2\left(\dfrac{1}{2}x^6-\dfrac{1}{2}x^2+x^4\right)\)

Answer 2

\(x^2\left(x^4-1\right)\left(x^2+2\right)+1=\left(x^6-x^2\right)\left(x^2+2\right)+1=x^8-x^4+2x^6-2x^2+1=2x^2\left(\dfrac{1}{2}\cdot x^6-\dfrac{1}{2}x^2+x^4-1\right)\)