Giải:
a) \(x^5-x^4-x^3+x^2\)
\(=x^2\left(x^3-x^2-x+1\right)\)
b) \(x^4-3x^3-x+3\)
\(=\left(x^4-x\right)-\left(3x^3-3\right)\)
\(=x\left(x^3-1\right)-3\left(x^3-1\right)\)
\(=\left(x^3-1\right)\left(x-3\right)\)
Chúc bạn học tốt!
Bài a :
\(x^5-x^4-x^3+x^2\)
\(=\left(x^5-x^4\right)-\left(x^3-x^2\right)\)
\(=x^4\left(x-1\right)-x^2\left(x-1\right)\)
\(=\left(x-1\right)\left(x^4-x^2\right)\)
\(=\left(x-1\right)\left(x^2-x\right)\left(x^2+x\right)\)
Bài b :
\(x^4-3x^3-x+3\)
\(=\left(x^4-x\right)-\left(3x^3-3\right)\)
\(=x\left(x^3-1\right)-3\left(x^3-1\right)\)
\(=\left(x^3-1\right)\left(x-3\right)\)
\(a,x^5-x^4-x^3+x^2\\ =x^2\left(x^3-x^2-x+1\right)\\ =x^2\left[x^2\left(x-1\right)-\left(x-1\right)\right]\\ =x^2\left(x-1\right)\left(x^2-1\right)\\ =x^2\left(x-1\right)^2\left(x+1\right)\\ b,x^4-3x^3-x+3\\ =x^3\left(x-3\right)-\left(x-3\right)\\ =\left(x-3\right)\left(x^3-1\right)\\ =\left(x-3\right)\left(x-1\right)\left(x^2+x+1\right)\)
Các bạn trên làm ko triệt để gì cả
