\(CaCO3-->CaO+CO2\)
\(n_{CaCO3}=\frac{100}{100}=1\left(mol\right)\)
\(n_{CO2}=n_{CaCO3}=1\left(mol\right)\)
\(m_{CO2}=1.44=44\left(g\right)\)
\(H\%=\frac{33}{44}.100\%=75\%\)
nCaCO3=100\100=1 mol
nCO2=33\44=0,75 mol
CaCO3-->CaO+CO2
1-------------------1 mol
H=0,75\1.100=75%