Gọi quãng đường AB là S
Ta có:
\(V_{tb}=\dfrac{S+S}{t_1+t_2}=\dfrac{2S}{t_1+t_2}\)(*)
Lại có:
\(t_1=\dfrac{S}{V_1}=\dfrac{S}{20}\left(1\right)\)
\(t_2=\dfrac{S}{V_2}=\dfrac{S}{10}\left(2\right)\)
Thay \(\left(1\right),\left(2\right)\) vào (*) ta được:
\(V_{tb}=\dfrac{2S}{\dfrac{S}{20}+\dfrac{S}{10}}=\dfrac{2}{\dfrac{1}{20}+\dfrac{1}{10}}\approx13,3\)(km/h)