(x2 - 1) (x2 + 4x + 3) = 192
<=> (x + 1)(x - 1)(x + 3)(x + 1) = 192
<=>(x2 + 2x − 3)(x2 + 2x + 1) = 192 (*)
Đặt t = x2 + 2x + 1
(*) => (t − 4)t = 192
<=> t2 − 4t − 192 = 0
<=> (t + 12)(t − 16) = 0
<=> t + 12 = 0 hoặc t - 16 = 0
<=>t = -12 hoặc t = 16
=> x