c)\(\left(4x+2\right)\left(x^2+1\right)\)
\(\Rightarrow\left[{}\begin{matrix}4x+2=0\\x^2+1=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=-\frac{2}{4}\\x\in\varnothing\end{matrix}\right.\)
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c)\(\left(4x+2\right)\left(x^2+1\right)\)
\(\Rightarrow\left[{}\begin{matrix}4x+2=0\\x^2+1=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=-\frac{2}{4}\\x\in\varnothing\end{matrix}\right.\)
VẬy...
Bài 1 giải các phương trình sau
a, \(\frac{5\left(1-2x\right)}{3}+\frac{x}{2}=\frac{3\left(x-5\right)}{4}-2\)
b, \(\left(x+2\right)^2+\left(x-1\right)\left(x+3\right)=2\left(x-4\right)\left(x+4\right)\)
c, \(\frac{3}{x-1}=\frac{3x+2}{1-x^2}-\frac{4}{x+1}\)
d, \(\frac{1}{x+1}+\frac{2x^2+1}{x^3+1}+\frac{2x^3-2x^2}{x^2-x+1}=2x\)
Bài 2 : Giải phương trình \(x^4+3x^3+6x+4=0\)
các bạn ơi ! giúp mik với đi ! mai kt rồi
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
1. \(^{x^3+x^2+x+1=0}\)
2. \(\left(2x-4\right)\left(3x+1\right)+\left(x-2\right)^2=0\)
3.\(x^2-5x+6=0\)
4. \(x^2-x-6=0\)
5. \(2x^2-3x=4\left(3-2x\right)\)
6. \(3\left(x-11\right)-2\left(x+11\right)=2011\)
7. \(\left(x-4\right)^2-\left(x+2\right)\left(x-6\right)=0\)
8. \(\left(x^2-9\right)\left(x+2\right)=0\)
9.\(\left(2x-1\right)^2=4x\left(x-1\right)\)
10. \(6\left(x+2\right)-5x=15\)
giải phương trình
a) \(\frac{x+1}{x-1}\)-\(\frac{x-1}{x+1}\)=\(\frac{4}{x^2-1}\)
b) \(\frac{8x^2}{3\left(1-4x^2\right)}\)=\(\frac{2x}{6x-3}\)-\(\frac{1+8x}{4+8x}\)
c) \(\frac{3}{4\left(x-5\right)}\)+\(\frac{15}{50-2x^2}\)= - \(\frac{7}{6\left(x+5\right)}\)
d) \(\frac{13}{\left(x-3\right)\left(2x+7\right)}\)+\(\frac{1}{2x+7}\)=\(\frac{6}{x^2-9}\)
giải phương trình
a) \(\left(5x+2\right)\left(x-7\right)=0\)
b) \(\left(x^2-1\right)\left(x+3\right)=0\)
c) \(x^2-x-6=0\)
d) \(x^2+x-12=0\)
e) \(15\left(x+9\right)\left(x-3\right)\left(x+21\right)=0\)
g) \(\left(x^2+1\right)\left(x^2+4x+4\right)=0\)
i) \(x^4+2x^3-2x^2+2x-3=0\)
h) \(x^2+5x+6=0\)
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
giải các phương trình sau:
a) \(\frac{5\left(x-1\right)+2}{6}-\frac{7x-1}{4}=\frac{2\left(2x+1\right)}{7}-5\)
b) \(\frac{4x-8}{2x^2+1}=0\)
Giaỉ các PT:
a) \(\left(x^2+1\right)^2=4\left(2x-1\right)\)
b) x(x+1)(x+2)(x+3)=24
c)\(\left(12x+7\right)^2\left(3x+2\right)\left(2x+1\right)=3\)
d)\(\left(x^2-9\right)^2=12x+1\)
e)\(\left(x-1\right)^5+\left(x+3\right)^5=242\left(x+1\right)\)
Giup mk vs mn
Giải pt bằng phương pháp đặt ẩn phụ
a,\(\left(x^2+2x+3\right)\left(x^2+2x+1\right)=3\)
b,\(x\left(x-1\right)\left(x^2-x+1\right)-6=0\)