c) \(\left(2x-4\right)^{2016}+\left|x^2-4\right|=0\Rightarrow\left\{{}\begin{matrix}\left(2x-4\right)^{2016}=0\\\left|x^2-4\right|=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}2x-4=0\\x^2-4=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}2x=4\\x^2=4\end{matrix}\right.\Rightarrow x=2\)
f) \(\left(3x-1\right)^2=\dfrac{4^{-1}-3.\left(\dfrac{3}{2}\right)^2}{5-\left(\dfrac{1}{3}\right)^{-1}}:\left[\left(\dfrac{6}{13}-\dfrac{1}{2}\right).2\right]\)
\(\left(3x-1\right)^2=\dfrac{\dfrac{1}{4}-3.\dfrac{9}{4}}{5-3}:\left[2.\dfrac{6}{13}-2.\dfrac{1}{2}\right]\)
\(\left(3x-1\right)^2=\dfrac{\dfrac{1}{4}-\dfrac{27}{4}}{2}:\left[\dfrac{12}{13}-1\right]\)
\(\left(3x-1\right)^2=\dfrac{-\dfrac{26}{4}}{2}:\left[-\dfrac{1}{13}\right]\)
\(\left(3x-1\right)^2=-\dfrac{13}{4}.\left[-13\right]\)
\(\left(3x-1\right)^2=\dfrac{169}{4}\)
\(\Rightarrow3x-1=\dfrac{13}{2}\) hoặc \(3x-1=-\dfrac{13}{2}\)
\(3x=\dfrac{15}{2}\) hoặc \(3x=-\dfrac{11}{2}\)
\(x=\dfrac{5}{2}\) hoặc \(x=-\dfrac{11}{6}\)
