Question

Mình cần gấp

Answer 1

\(\dfrac{1}{7}+\dfrac{1}{7}:\dfrac{5}{3}+\dfrac{3}{5}\\ =\dfrac{1}{7}+\dfrac{1}{7}.\dfrac{3}{5}+\dfrac{3}{5}\\ =\dfrac{1}{7}+\dfrac{3}{35}+\dfrac{3}{5}\\ =\dfrac{5}{35}+\dfrac{3}{35}+\dfrac{21}{35}\\ =\dfrac{5+3+21}{35}\\ =\dfrac{29}{35}\)

Answer 2

\(\dfrac{1}{7}-\dfrac{1}{7}:\dfrac{5}{3}+\dfrac{3}{5}=\dfrac{1}{7}-\dfrac{3}{35}+\dfrac{3}{5}=\dfrac{2}{35}+\dfrac{3}{5}=\dfrac{23}{35}\)

Answer 3

\(\dfrac{1}{7}-\dfrac{1}{7}:\dfrac{5}{3}+\dfrac{3}{5}=\dfrac{1}{7}-\dfrac{3}{35}+\dfrac{3}{5}=\dfrac{23}{35}\)

Answer 4

\(\dfrac{1}{7}\)-\(\dfrac{1}{7}\):\(\dfrac{5}{3}\)+\(\dfrac{3}{5}\)=\(\dfrac{1}{7}-\dfrac{1}{7}\).\(\dfrac{3}{5}+\dfrac{3}{5}\)=\(\dfrac{1}{7}-\dfrac{3}{35}+\dfrac{3}{5}\)=\(\dfrac{5}{35}-\dfrac{3}{35}+\dfrac{21}{35}\)

=\(\dfrac{5-3+21}{35}=\dfrac{23}{35}\)