Giới hạn khi x tiến tới đâu bạn?
Bài 1: Giới hạn của dãy số
Các câu hỏi tương tự
Tìm các giới hạn sau :
Alimlimits_{xrightarrow0}frac{sqrt[3]{x+1}-1}{sqrt[4]{2x+1}-1}
Blimlimits_{xrightarrow7}frac{sqrt[3]{4x-1}sqrt{x-2}}{sqrt[4]{2x+2}-2}
Climlimits_{xrightarrow0}frac{sqrt{left(2x+1right)left(3x+1right)left(4x+1right)}-1}{x}
Dlimlimits_{xrightarrow0}frac{sqrt{1+4x}-sqrt[3]{1+6x}}{x^2}
Elimlimits_{xrightarrow0}frac{sqrt[m]{1+ax}-sqrt[n]{1+bx}}{x}
Giup mình vớiii
Đọc tiếp
Tìm các giới hạn sau :
A=\(\lim\limits_{x\rightarrow0}\frac{\sqrt[3]{x+1}-1}{\sqrt[4]{2x+1}-1}\)
B=\(\lim\limits_{x\rightarrow7}\frac{\sqrt[3]{4x-1}\sqrt{x-2}}{\sqrt[4]{2x+2}-2}\)
C=\(\lim\limits_{x\rightarrow0}\frac{\sqrt{\left(2x+1\right)\left(3x+1\right)\left(4x+1\right)}-1}{x}\)
D=\(\lim\limits_{x\rightarrow0}\frac{\sqrt{1+4x}-\sqrt[3]{1+6x}}{x^2}\)
E=\(\lim\limits_{x\rightarrow0}\frac{\sqrt[m]{1+ax}-\sqrt[n]{1+bx}}{x}\)
Giup mình vớiii
a) lim ( \(\sqrt{x^2-x+1}-\sqrt{x^2+x+1}\)
x-> +∞
b) lim \(\dfrac{\sqrt{4x+1}-3}{x^2-4}\)
x-> 2
c) lim \(\dfrac{\sqrt{2x+5}-1}{x^2-4}\)
x-> -2
a) lim \(\dfrac{x\sqrt{x^2+1}-2x+1}{^3\sqrt{2x^3-2}+1}\)
x-> -∞
b) lim \(\dfrac{\left(2x+1\right)^3\left(x+2\right)^4}{\left(3-2x\right)^7}\)
x-> -∞
c) lim \(\dfrac{\sqrt{4x^2+x}+^3\sqrt{8x^3+x-1}}{^4\sqrt{x^4+3}}\)
x-> +∞
a) lim \(\dfrac{2x-\sqrt{3x^2+2}}{5x+\sqrt{x^2+2}}\)
x-> +∞
b) lim \(\sqrt{\dfrac{x^2+1}{2x^4+x^2-3}}\)
x-> ∞
a) lim ( x2+x-1)
x-> -∞
b) lim ( \(\sqrt{x^2+x+1}-2\sqrt{x^2-x}+x\))
x-> +∞
c) lim x\(\left(\sqrt{x^2+2x}-2\sqrt{x^2+x}+x\right)\)
x-> +∞
27 tháng 1 2021 lúc 18:55
Tìm giơi han:
a) lim (x-> \(+\infty\)) \(\dfrac{\sqrt{x^2+1}+x}{5-2x}\)
b) lim (x->4) \(\left(\dfrac{\sqrt{15x+4}-\sqrt{x-3}-3}{-x+4}\right)\)
sorry, e k bt nhâp lim ..
tìm các giới hạn
a)lim(sqrt{n+1}-sqrt{n})
b)limleft(sqrt{n+5n+1}-sqrt{n^2-n}right)
c)limleft(sqrt{3n^2+2n-1}-sqrt{3n^2-4n+8}right)
d)limfrac{2^n+6^n-4^{n+1}}{3^n+6^{n+1}}
e)limfrac{3^n-4^n+5^n}{3^n+4^n-5^n}
f)limfrac{1+3+5+.....+left(2n+1right)}{3n^2+4}
g)lim[frac{1}{1.2}+frac{1}{2.3}+....+frac{1}{nleft(n+1right)}]
h)limfrac{1^2+2^2+3^2+.....+n^2}{nleft(n+1right)left(n+2right)}
Đọc tiếp
tìm các giới hạn
a)lim(\(\sqrt{n+1}-\sqrt{n}\))
b)lim\(\left(\sqrt{n+5n+1}-\sqrt{n^2-n}\right)\)
c)lim\(\left(\sqrt{3n^2+2n-1}-\sqrt{3n^2-4n+8}\right)\)
d)lim\(\frac{2^n+6^n-4^{n+1}}{3^n+6^{n+1}}\)
e)lim\(\frac{3^n-4^n+5^n}{3^n+4^n-5^n}\)
f)lim\(\frac{1+3+5+.....+\left(2n+1\right)}{3n^2+4}\)
g)lim[\(\frac{1}{1.2}+\frac{1}{2.3}+....+\frac{1}{n\left(n+1\right)}\)]
h)lim\(\frac{1^2+2^2+3^2+.....+n^2}{n\left(n+1\right)\left(n+2\right)}\)
lim ( \(^4\sqrt{16x^4+3x+1}-\sqrt{4x^2+2}\))
x-> +∞
limleft(sqrt[3]{n-n^3}+sqrt{n^2+3n}right)
limleft(sqrt{n-2sqrt{n}}-sqrt{n+4}right)
limleft(sqrt[3]{3n^2+n^3}-nright)
limleft(sqrt[3]{n^3+6n}-sqrt{n^2-4n}right)
limfrac{-3^{n+1}+4^{n+1}}{5.3^n+3.2^{2n-1}}
limleft(frac{3^{2n}-5^{n+1}+7^{n+1}}{3^{n+2}+5^n+2^{3n+2}}right)
limleft(frac{6^{n+1}+3^{2n+5}}{3^{2n+3}-2^{2n-1}}right)
Đọc tiếp
\(lim\left(\sqrt[3]{n-n^3}+\sqrt{n^2+3n}\right)\)
\(lim\left(\sqrt{n-2\sqrt{n}}-\sqrt{n+4}\right)\)
\(lim\left(\sqrt[3]{3n^2+n^3}-n\right)\)
\(lim\left(\sqrt[3]{n^3+6n}-\sqrt{n^2-4n}\right)\)
\(lim\frac{-3^{n+1}+4^{n+1}}{5.3^n+3.2^{2n-1}}\)
\(lim\left(\frac{3^{2n}-5^{n+1}+7^{n+1}}{3^{n+2}+5^n+2^{3n+2}}\right)\)
\(lim\left(\frac{6^{n+1}+3^{2n+5}}{3^{2n+3}-2^{2n-1}}\right)\)