\(\left|x-1.5\right|+\left|2.5-x\right|\ge0\forall x\)
Dấu '='xảy ra khi \(\left\{{}\begin{matrix}x=1.5\\x=2.5\end{matrix}\right.\Leftrightarrow x\in\varnothing\)
Tìm \(x\in\mathbb{Q}\), biết :
a) \(\left|2,5-x\right|=1,3\)
b) \(1,6-\left|x-0,2\right|=0\)
c) \(\left|x-1,5\right|+\left|2,5-x\right|=0\)
1) Trong các khẳng định sau đây, khẳng định nào đúng?
a) \(\left|-2,5\right|=2,5\) b) \(\left|-2,5\right|=-2,5\) c) \(\left|-2,5\right|=-\left(-2,5\right)\)
2) Tìm x biết:
a) \(\left|x\right|=\dfrac{1}{5}\) b)\(\left|x\right|=0,37\)
c) \(\left|x\right|=0\) d) \(\left|x\right|=1\dfrac{2}{3}\)
tim x
a,\(\left|2x-1,6\right|-2,3=1,4\)
b\(5,4-\left|3x-1,2\right|=5,5\)
c,\(\left|x+1,3\right|+\left|x+2,4\right|=4x\)
d, \(\left|x-1,2\right|+\left|2,5-x\right|=0\)
giup minh nhe minh dang can gap
tìm x biết:
a) \(\left|1,5.x\right|-\)\(\left|-0,6\right|=-2+\left|0,4\right|\)
b) \(\left|x+\dfrac{7}{3}\right|-\left|-\dfrac{1}{3}\right|=0\)
các bn giúp mk vs nha mk cảm ơn lắm lắm.
*Rút gọn biểu thức:
a, A = \(\left|x-2,5\right|-\left|x-1,7\right|\)
b, B = \(\left|x-_5^1\right|-\left|x-^2_5\right|\)
Bài 1: Tìm x biết
a) \(\left|x-\dfrac{1}{3}\right|=2\dfrac{1}{5}\)
b) \(\left|-x+\dfrac{2}{5}\right|+\dfrac{1}{2}=3,5\)
c) \(\left|x+\dfrac{1}{4}\right|-\dfrac{3}{4}=5\%\)
Bài 2: Rút gọn biểu thức sau nếu x < -1,3
A= \(\left|x+1,3\right|-\left|x-2,5\right|\)
B= \(\left|-x-1,3\right|-\left|x-2,5\right|\)
Bài 3: Tìm x biết
a) \(\left|x-1\right|=x-1\)
b) \(\left|x-1\right|=1-x\)
c) \(x-1< \left|x-1\right|\)
d) \(x-1>\left|x-1\right|\)
Bài 4 : Tìm x,y biết :
a)\(3\dfrac{1}{4}-\dfrac{1}{4}\left|x-0,25\right|=\dfrac{1}{4}\)
b)\(\left|x-3\right|=-4\)
c)\(\left|x-\dfrac{1}{2}\right|+1=0\)
d)\(\left|x-\dfrac{1}{5}\right|=\left|\dfrac{3}{4}-2x\right|\)
e)\(\left|x+2\right|3=0\)
f)\(\left|2x-1\right|-\left|x+2\right|=0\)
g)\(\left|x+2\right|+\left|y-1\right|=0\)
h)\(\left|2x\right|+\left|y+\dfrac{1}{4}\right|=0\)
a, Tìm GTNN của B= 4,2 + \(\left|x+1,5\right|\)
b,Tìm GTLN của C= \(\dfrac{4}{5}-\left|2x+1\right|\)
1. Tìm x:
a) \(\left|3x-5\right|-\left|x+2\right|=0\)
b)\(\left|3x-5\right|+\left|x+2\right|=0\)
c)\(\left|3x-5\right|-x+2=0\)
d)\(\dfrac{11}{2}\le\left|x\right|< \dfrac{17}{2}\)
e)\(\dfrac{11}{2}\le\left|x+2\right|\le\dfrac{17}{2}\)
