Question

\(\left(\dfrac{\sqrt{1}}{\sqrt{7}}-\sqrt{\dfrac{16}{7}}+\sqrt{\dfrac{9}{7}}\right)\) : \(\sqrt{7}\)

Answer 1

\(=\left(\dfrac{1-4+3}{\sqrt{7}}\right):\sqrt{7}=0\)

Answer 2

\(=\dfrac{1}{\sqrt{7}}:\sqrt{7}-\sqrt{\dfrac{16}{7}}:\sqrt{7}+\sqrt{\dfrac{9}{7}}:\sqrt{7}\\ =\dfrac{1}{7}-\dfrac{4}{\sqrt{7}}.\dfrac{1}{\sqrt{7}}+\dfrac{3}{\sqrt{7}}.\dfrac{1}{\sqrt{7}}\\ =\dfrac{1}{7}-\dfrac{4}{7}+\dfrac{3}{7}=0\)

Answer 3

\(=\left(\dfrac{1-4+3}{\sqrt{7}}\right):\sqrt{7}=0\)