Nhận thấy \(y=0\) không phải nghiệm
\(\Leftrightarrow\left\{{}\begin{matrix}x^3-2x^2y+3y=0\\2xy^2-y^3-3y=0\end{matrix}\right.\)
\(\Rightarrow x^3-2x^2y+2xy^2-y^3=0\)
\(\Leftrightarrow\left(x-y\right)^3+xy\left(x-y\right)=0\)
\(\Leftrightarrow\left(x-y\right)\left(x^2-xy+y^2\right)=0\)
\(\Leftrightarrow x=y\Rightarrow2x^2-x^2=3\Rightarrow x=y=\pm\sqrt{3}\)