(1) \(\Leftrightarrow\left(x-y\right)\left(x+2y+1\right)=0\)
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Bài 3: Giải hệ phương trình bằng phương pháp thế
Các câu hỏi tương tự
Giải hệ phương trình \(\left\{{}\begin{matrix}x^2-xy+y-7=0\\x^2+xy-2y=4\left(x-1\right)\end{matrix}\right.\)
Giải hpt
a)\(\left\{{}\begin{matrix}x+y+z=1\\x+2y+4z=8\\x+3y+9z=27\end{matrix}\right.\) b)\(\left\{{}\begin{matrix}x^2+y^2+x+y=62\\xy=24\end{matrix}\right.\) c)\(\left\{{}\begin{matrix}\dfrac{3}{2x+y}+z=2\\2y-3z=4\\\dfrac{2}{2x+y}-y=\dfrac{3}{2}\end{matrix}\right.\)
giải các hệ phương trình sau:
left{{}begin{matrix}2x+dfrac{Y}{sqrt{4X^{2^{ }}+1}+2X}+Y^{2^{ }}04left(dfrac{X}{Y}right)^{2^{ }}+2sqrt{4X^{2^{ }}+1}+Y^{2^{ }}3end{matrix}right.
left{{}begin{matrix}x+y+z6xy+yz+zx11xyz6end{matrix}right.
left{{}begin{matrix}x^{3^{ }}-y^{3^{ }}-15y-143left(2y^{2^{ }}-xright)4x^{3^{ }}+6xy+15x+30end{matrix}right.
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giải các hệ phương trình sau:
\(\left\{{}\begin{matrix}2x+\dfrac{Y}{\sqrt{4X^{2^{ }}+1}+2X}+Y^{2^{ }}=0\\4\left(\dfrac{X}{Y}\right)^{2^{ }}+2\sqrt{4X^{2^{ }}+1}+Y^{2^{ }}=3\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x+y+z=6\\xy+yz+zx=11\\xyz=6\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x^{3^{ }}-y^{3^{ }}-15y-14=3\left(2y^{2^{ }}-x\right)\\4x^{3^{ }}+6xy+15x+3=0\end{matrix}\right.\)
1)left{{}begin{matrix}x^2-y^2-2x+2y0x^2-3xy+5y^2-30end{matrix}right.
2)left{{}begin{matrix}frac{1}{x}+frac{1}{1-y}1frac{1}{x-1}-frac{1}{y}2end{matrix}right.
3)left{{}begin{matrix}x^2-4x+30x^2+xy+y^21end{matrix}right.
4)left{{}begin{matrix}x^2+y^2+x+y2left(x+1right)^2-left(y+2right)^20end{matrix}right.
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1)\(\left\{{}\begin{matrix}x^2-y^2-2x+2y=0\\x^2-3xy+5y^2-3=0\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}\frac{1}{x}+\frac{1}{1-y}=1\\\frac{1}{x-1}-\frac{1}{y}=2\end{matrix}\right.\)
3)\(\left\{{}\begin{matrix}x^2-4x+3=0\\x^2+xy+y^2=1\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}x^2+y^2+x+y=2\\\left(x+1\right)^2-\left(y+2\right)^2=0\end{matrix}\right.\)
Giải hpt
\(\left\{{}\begin{matrix}y^2-xy+1=0\\x^2+y^2+2x+2y2+1=0\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x^2y^2-xy-2=0\\x^2+y^2=x^2y^2\end{matrix}\right.\)
Giải HPT: \(\left\{{}\begin{matrix}\left(x+1\right)\left(y-1\right)=2\\\left(x-3\right)\left(y+1\right)=-6\end{matrix}\right.\)
Giải hệ phương trình
left{{}begin{matrix}4left(2x-y+3right)-3left(x-2y+3right)483left(3x-4y+3right)+4left(4x-2y-9right)48end{matrix}right.
left{{}begin{matrix}6left(x+yright)8+2x-3y5left(y-xright)5+3x+2yend{matrix}right.
left{{}begin{matrix}-2left(2x+1right)+1,53left(y-2right)-6x11,5-4left(3-xright)2y-left(5-xright)end{matrix}right.
left{{}begin{matrix}dfrac{8x-5y-3}{7}+dfrac{11y-4x-7}{5}12dfrac{9x+4y-13}{5}-dfrac{3left(x-2right)}{4}15end{matrix}right.
left{{}begin{matrix}2sqrt{3}x-sqrt{5}y2...
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Giải hệ phương trình
\(\left\{{}\begin{matrix}4\left(2x-y+3\right)-3\left(x-2y+3\right)=48\\3\left(3x-4y+3\right)+4\left(4x-2y-9\right)=48\end{matrix}\right.\)
\(\left\{{}\begin{matrix}6\left(x+y\right)=8+2x-3y\\5\left(y-x\right)=5+3x+2y\end{matrix}\right.\)
\(\left\{{}\begin{matrix}-2\left(2x+1\right)+1,5=3\left(y-2\right)-6x\\11,5-4\left(3-x\right)=2y-\left(5-x\right)\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\dfrac{8x-5y-3}{7}+\dfrac{11y-4x-7}{5}=12\\\dfrac{9x+4y-13}{5}-\dfrac{3\left(x-2\right)}{4}=15\end{matrix}\right.\)
\(\left\{{}\begin{matrix}2\sqrt{3}x-\sqrt{5}y=2\sqrt{6}-\sqrt{15}\\3x-y=3\sqrt{2}-\sqrt{3}\end{matrix}\right.\)
3 tháng 12 2021 lúc 20:17
Giải hệ phương trìnha)left{{}begin{matrix}x+ydfrac{x-3}{2}x+2ydfrac{2-4y}{15}end{matrix}right. b)left{{}begin{matrix}dfrac{1}{x}+dfrac{1}{y}-1dfrac{3}{x}-dfrac{2}{y}7end{matrix}right.c)left{{}begin{matrix}sqrt{x+3}-2sqrt{y+1}22sqrt{x+3}+sqrt{y+1}4end{matrix}right. d)left{{}begin{matrix}dfrac{7}{sqrt{x}-7}-dfrac{4}{sqrt{y}+6}dfrac{5}{3}dfrac{5}{sqrt{x}-7}+dfrac{3}{sqrt{y}+6}2dfrac{1}{9}end{matrix}right.
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Giải hệ phương trình
a)\(\left\{{}\begin{matrix}x+y=\dfrac{x-3}{2}\\x+2y=\dfrac{2-4y}{15}\end{matrix}\right.\) b)\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=-1\\\dfrac{3}{x}-\dfrac{2}{y}=7\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\sqrt{x+3}-2\sqrt{y+1}=2\\2\sqrt{x+3}+\sqrt{y+1}=4\end{matrix}\right.\) d)\(\left\{{}\begin{matrix}\dfrac{7}{\sqrt{x}-7}-\dfrac{4}{\sqrt{y}+6}=\dfrac{5}{3}\\\dfrac{5}{\sqrt{x}-7}+\dfrac{3}{\sqrt{y}+6}=2\dfrac{1}{9}\end{matrix}\right.\)