\(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)
\(\Rightarrow\left[\begin{matrix}5x-1=0\\2x-\frac{1}{3}=0\end{matrix}\right.\Rightarrow\left[\begin{matrix}5x=1\\2x=\frac{1}{3}\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=\frac{1}{5}\\x=\frac{1}{6}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{1}{5};\frac{1}{6}\right\}\)