\(\left|2,5-x\right|=1,3\)
=> \(\left[{}\begin{matrix}2,5-x=1,3\\2,5-x=-1,3\end{matrix}\right.\) => \(\left[{}\begin{matrix}x=2,5-1,3\\x=2,5-\left(-1,3\right)\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=1,2\\x=3,8\end{matrix}\right.\)
Vậy \(x\in\left\{1,2;3,8\right\}.\)
Chúc bạn học tốt!
\(\left|2,5-x\right|=1,3\)
\(\Leftrightarrow\left[{}\begin{matrix}2,5-x=1,3\\2,5-x=-1,3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2,5-1,3\\x=2,5-\left(-1,3\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1,2\\x=3,8\end{matrix}\right.\)
Vậy : \(x\in\left\{1,2;3,8\right\}\)
|2,5 - x| = 1,3
⇔2,5 - x = 1,3 hoặc 2,5 - x = -1,3
x = 1,2 x = 3,8
Vậy x = 1,2; x = 3,8
|2,5−x|=1,3|2,5−x|=1,3
=> [2,5−x=1,32,5−x=−1,3[2,5−x=1,32,5−x=−1,3 => [x=2,5−1,3x=2,5−(−1,3)[x=2,5−1,3x=2,5−(−1,3)
=> [x=1,2x=3,8[x=1,2x=3,8
Vậy x∈{1,2;3,8}.
tick cho mình nha