Question

Làm tính nhân :

a) \(\left(x^2y^2-\dfrac{1}{2}xy+2y\right)\left(x-2y\right)\)

b) \(\left(x^2-xy+y^2\right)\left(x+y\right)\)

Answer 1

a) (x²y² – xy + 2y)(x – 2y)

= x²y². X + x²y²(-2y) + (xy) . x + (-xy)(-2y) + 2y . x + 2y(-2y)

= x³y² – 2x²y³- x²y + xy² + 2xy – 4y²

b) (x² – xy + y²)(x + y) = x² . x + x². y + (-xy) . x + (-xy) . y + y² . x + y². y

= x³ + x². y - x². y - xy² + xy² + y³

= x³ - y³

Answer 2

a) (x²y² – xy + 2y)(x – 2y)

= x²y². X + x²y²(-2y) + (xy) . x + (-xy)(-2y) + 2y . x + 2y(-2y)

= x³y² – 2x²y³- x²y + xy² + 2xy – 4y²

b) (x² – xy + y²)(x + y) = x² . x + x². y + (-xy) . x + (-xy) . y + y² . x + y². y

= x³ + x². y - x². y - xy² + xy² + y³

= x³ - y³

Answer 3

a) (x²y² – xy + 2y)(x – 2y)

= x²y². X + x²y²(-2y) + (xy) . x + (-xy)(-2y) + 2y . x + 2y(-2y)

= x³y² – 2x²y³- x²y + xy² + 2xy – 4y²

b) (x² – xy + y²)(x + y) = x² . x + x². y + (-xy) . x + (-xy) . y + y² . x + y². y

= x³ + x². y - x². y - xy² + xy² + y³

= x³ - y³