Question

làm tính chia

(a-b)¹⁰: \(\dfrac{1}{3}\) (a-b)³

tính giá trị biểu thức

(a-b+c)⁵ : (b-a-c)² tại a = 5 b= 2 c= \(-3\dfrac{1}{2}\)

Answer 1

Tính giá trị biểu thức:

\(\left(a-b+c\right)^5:\left(b-a-c\right)^2\)

\(=\left(a-b+c\right)^5:\left[-\left(a-b+c\right)^2\right]\)

\(=\left(a-b+c\right)^5:\left(a-b+c\right)^2\)

\(=\left(a-b+c\right)^3\)

\(=\left(5-2+\left(-3\dfrac{1}{2}\right)\right)^3\)

\(=\left(3-\dfrac{7}{2}\right)=-\dfrac{1}{2}\)

Answer 2

\(\left(a-b\right)^{10}:\dfrac{1}{3}\left(a-b\right)^3\)

\(=\left(1:\dfrac{1}{3}\right)\left[\left(a-b\right)^{10}:\left(a-b\right)^3\right]\)

\(=3\left(a-b\right)^7\)