Question

làm tính chia

e) (\(\dfrac{1}{3}\)a³b+\(\dfrac{1}{3}\)a²b²-\(\dfrac{1}{4}\)ab³):5ab

f) (-\(\dfrac{2}{3}\)x⁵y²+\(\dfrac{3}{4}\)x⁴y³-\(\dfrac{4}{5}\)x³y⁴):6x²y²

g) (\(\dfrac{3}{4}\)a⁶b³+\(\dfrac{6}{5}\)a³b⁴-\(\dfrac{5}{10}\)ab⁵):(\(\dfrac{3}{5}\)ab³) gải giùm mình cần gắp bữa nay học òi

Answer 1

\(e,\)

\(\left(\dfrac{1}{3}a^3b+\dfrac{1}{3}a^2b^2-\dfrac{1}{4}ab^3\right):5ab\)

\(=\dfrac{1}{15}a^2+\dfrac{1}{15}ab-\dfrac{1}{20}b^2\)

\(f,\)

\(\left(-\dfrac{2}{3}x^5y^2+\dfrac{3}{4}x^4y^3-\dfrac{4}{5}x^3y^4\right):6x^2y^2\)

\(=-\dfrac{1}{9}x^3+\dfrac{1}{8}x^2y-\dfrac{2}{15}xy^2\)

\(g,\)

\(\left(\dfrac{3}{4}a^6b^3+\dfrac{6}{5}a^3b^4-\dfrac{5}{10}ab^5\right):\left(\dfrac{3}{5}ab^3\right)\)

\(=\dfrac{5}{4}a^5+2a^2b-\dfrac{5}{6}b^2\)