Question

Không tính góc a.Tính tỉ số lượng giác góc a biết cotga=40/9

 

Answer 1

 \(tana.cota=1\Rightarrow tana=\dfrac{1}{cota}=\dfrac{1}{\dfrac{40}{9}}=\dfrac{9}{40}\)

\(1+tan^2a=\dfrac{1}{cos^2a}=1+\left(\dfrac{9}{40}\right)^2=\dfrac{1681}{1600}\\ \Rightarrow cos^2a=\dfrac{1600}{1681}\\ \Rightarrow cosa=\dfrac{40}{41}\)

\(1+cot^2a=\dfrac{1}{sin^2a}=1+\left(\dfrac{40}{9}\right)^2=\dfrac{1681}{81}\\ \Rightarrow sin^2a=\dfrac{81}{1681}\\ \Rightarrow sina=\dfrac{9}{41}\)