\(\lim\limits_{x\rightarrow1}\dfrac{x^2-3x+2}{x-1}=\lim\limits_{x\rightarrow1}\dfrac{\left(x-1\right)\left(x-2\right)}{x-1}=\lim\limits_{x\rightarrow1}\left(x-2\right)=1-2=-1\)
\(\lim\limits_{x\rightarrow1}\dfrac{x^2-3x+2}{x-1}=\lim\limits_{x\rightarrow1}\dfrac{\left(x-1\right)\left(x-2\right)}{x-1}=\lim\limits_{x\rightarrow1}\left(x-2\right)=1-2=-1\)
Kết quả giới hạn \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{x+3}-2}{x-1}\) bằng:
A. 0
B. \(\dfrac{1}{2}\)
C. \(\dfrac{1}{4}\)
D. \(\dfrac{1}{3}\)
Kết quả giới hạn \(\lim\limits_{x\rightarrow2}\dfrac{x^2-4}{x-2}\) bằng:
A. 0
B. -4
C. 2
D. 4
Tính giới hạn sau:
\(\lim\limits_{x\rightarrow1}\dfrac{\left(x^2+3x+1\right)\sqrt{1+3x}-10}{x^2-1}\)
tìm giới hạn \(\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt{4x^2+2x-1}-x}{3x-2}\)
Tính giới hạn
a) \(\lim\limits_{x\rightarrow-\infty}\dfrac{x+3}{3x-1}=\dfrac{1}{3}\)
b) \(\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt{x^2-2x+4}-x}{3x-1}\)
Tính các giới hạn
\(\lim\limits_{x\rightarrow1}\dfrac{x^2-\sqrt{x}}{\sqrt{x}-1}\)
Tìm giới hạn:
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt[4]{x}-1}{x^3+x-2}\)
Tìm giới hạn:
a, \(\lim\limits_{x\rightarrow-1}\dfrac{\sqrt[3]{x}-x}{x^2-x}\)
b, \(\lim\limits_{x\rightarrow1}\dfrac{x^3-x^2-x+1}{x^3-3x+2}\)
Tính các giới hạn sau:
a) \(\lim\limits_{x\rightarrow0^-}\dfrac{2\left|x\right|+x}{x^2-x}\)
b) \(\lim\limits_{x\rightarrow-\infty}\left(\sqrt{x^2-x}-\sqrt{x^2-1}\right)\)
c) \(\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt[3]{1+x^4+x^6}}{\sqrt{1+x^3+x^4}}\)