Zn + 2HCl → ZnCl2 + H2
Chất rắn sau pư là Cu
\(\Rightarrow m_{Cu}=2,5\left(g\right)\)
\(n_{H_2}=\frac{6,72}{22,4}=0,3\left(mol\right)\)
a) Theo pt: \(n_{HCl}=2n_{H_2}=2\times0,3=0,6\left(mol\right)\)
\(\Rightarrow V_{ddHCl}=\frac{0,6}{2}=0,3\left(l\right)\)
b) Theo pT: \(n_{Zn}=n_{H_2}=0,3\left(mol\right)\)
\(\Rightarrow m_{Zn}=0,3\times65=19,5\left(g\right)\)
\(\%m_{Zn}=\frac{19,5}{19,5+2,5}\times100\%=88,64\%\)
\(\%m_{Cu}=100\%-88,64\%=11,36\%\)