\(n_{H2SO4}=1.0,2=0,2\left(mol\right)\)
a. Gọi số mol CuO và FeO là a và b
\(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\)
a____ a_____________
\(FeO+H_2SO_4\rightarrow FeSO_4+H_2O\)
b_____ b______________
\(\left\{{}\begin{matrix}80a+72b=15\\a+b=0,2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,075\\b=0,125\end{matrix}\right.\)
\(m_{CuO}=0,075.80=6\left(g\right)\)
\(m_{FeO}=15-6=9\left(g\right)\)
b. \(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(FeO+2HCl\rightarrow FeCl_2+H_2O\)
Ta có nHCl=2nCuO+2nFeO=0,4
\(m_{HCl}=0,4.36,5=14,6\left(g\right)\)
\(m_{dd_{HCl}}=\frac{14,6}{30\%}=48,67\left(g\right)\)
