a) Zn + H2SO4 --> ZnSO4 + H2
b) \(n_{H_2}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)
Zn + H2SO4 --> ZnSO4 + H2
0,3<-------------------------0,3
\(\left\{{}\begin{matrix}\%Zn=\dfrac{0,3.65}{30}.100\%=65\%\\\%Cu=100\%-65\%=35\%5\%\end{matrix}\right.\)
Cu Không Pư vs H2SO4
\(n_{H_2}=\dfrac{6.72}{22.4}\)=0.3 (mol)
Zn + 2HCl \(\rightarrow\)ZnCl2+H2\(\uparrow\)
0.3\(\leftarrow\) 0.3 (mol)
mZn=0.3*65=19.5(g)
mCu=30-19.5=10.5(g)
\(\left\{{}\begin{matrix}\%Zn=\dfrac{19.5}{30}\cdot100=65\%\\\%Cu=\dfrac{10.5}{30}\cdot100=35\%\end{matrix}\right.\)
c)
\(n_{H_2}=0.3\left(mol\right)\)
2A+ 6HCl \(\rightarrow\)2ACl3+3H2\(\uparrow\)
nA=\(\dfrac{0.3\cdot2}{3}\)=0.2 (mol)
=)MA=\(\dfrac{11.2}{0.2}\)=56
-> A là Fe
