a. (x + 2).5=50
x+2=50:5
x+2=10
x=10:2
x=5
b, (28+x) -3=3^10:3^7
(28+x) -3=3^3
(28+x) -3=27
28+x=27+3
28+x=30
x=30-28
x=2
a) x+2=\(\frac{50}{5}\)=10
⇒x=10-2=8
b)28+x-3=310-7=33=27
25+x=27
x=2
a ) (x + 2) . 5 = 50
(x + 2) = 50 : 5
x + 2 = 10
x = 10 - 2
➩ x = 8
b ) (28 + x) - 3 = 310 : 37
(28 + x) - 3 = 33
(28 + x) - 3 = 27
28 + x = 27 + 3
28 + x = 30
x = 30 - 28
➩ x = 2
a) Ta có: \(\left(x+2\right)\cdot5=50\)
\(\Leftrightarrow x+2=10\)
hay x=8
Vậy: x=8
b) Ta có: \(\left(28+x\right)-3=3^{10}:3^7\)
\(\Leftrightarrow28+x=3^3-3=24\)
hay x=-4
Vậy: x=-4
chỉ ghi kết quả: a) 10 b) 2
a) (x+2).5=50
x+2=50:5
x+2=10
x=10-2
x=8.
Vậy x=8.
b) (28+x)-3=310:37
(28+x)-3=33
(28+x)-3=27
28+x=27+3
28+x=30
x=30-28
x=2.
Vậy x=2.