Bài số 3:
\(a,PTHH:2Na+H_2SO_4\to Na_2SO_4+H_2\\ b,\text {Bảo toàn KL: }m_{Na}+m{H_2SO_4}=m_{Na_2SO_4}+m_{H_2}\\ c,m_{Na_2SO_4}=4,6+9,8-0,2=14,2(g)\)
Bài số 4:
\(a,PTHH:SO_3+2KOH\to K_2SO_4+H_2O\\ b,\text {Bảo toàn KL: }m_{SO_3}+m_{KOH}=m_{K_2SO_4}+m_{H_2O}\\ c,m_{K_2SO_4}=16+22,4-3,6=34,8(g)\)
Bài số 1:
\(1,2KNO_3\buildrel{{t^o}}\over\to 2KNO_2+O_2\\ 2,2KMnO_4\buildrel{{t^o}}\over\to K_2MnO_4+MnO_2+O_2\\ 3,2KClO_3\xrightarrow[MnO_2]{t^o} 2KCl+3O_2\\ 4,Al_2(SO_4)_3+3Ca(OH)_2\to 2Al(OH)_3 \downarrow+3CaSO_4\\ 5,2Fe(NO_3)_3+3Ba(OH)_2\to 2Fe(OH)_3\downarrow+3Ba(NO_3)_2\)
Bài số 2:
\(1,N_2+H_2\xrightarrow{t^0,xt}NH_3\\ 2,O_2+2Pb\xrightarrow{t^o}2PbO\\ 3,Zn+S\xrightarrow{t^o}ZnS\\ 4,Mg+2HCl\to MgCl_2+H_2\\ 5,2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ 6,Fe_2O_3+3H_2\xrightarrow{t^o}2Fe+3H_2O\\ 7,CuO+H_2\xrightarrow{t^o}Cu+H_2O\\ 8,PbO+CO\xrightarrow{t^o}Pb+CO_2\\ 9,Fe_3O_4+4CO\xrightarrow{t^o}3Fe+4CO_2\\ 10,BaO+2HCl\to BaCl_2+H_2O\)
