Question

Giúp mình nhé

Answer 1

\(\left(\dfrac{1+b\sqrt{b}}{1+\sqrt{b}}-\sqrt{b}\right)\left(\dfrac{1+\sqrt{b}}{1-b}-b\right)^2\)

=\(\left[\dfrac{\left(1+\sqrt{b}\right)\left(1-\sqrt{b}+b\right)}{1+\sqrt{b}}-\sqrt{b}\right]\)\(\left[\dfrac{\left(1+\sqrt{b}\right)}{\left(1-\sqrt{b}\right)\left(1+\sqrt{b}\right)}\right]^2\)

=\(\left(1-2b+b\right)\left(\dfrac{1}{1-\sqrt{b}}\right)^2\)

=\(\left(1-\sqrt{b}\right)^2\left(\dfrac{1^2}{\left(1-\sqrt{b}\right)^2}\right)\)

Answer 2

kết quả còn bước nữa, kết quả cuối cùng

=1

Answer 3

Ảnh quá rõ!!!