Question

GIUP MINH CAU NAY VOI

 

Answer 1

\(A=\dfrac{\sqrt{x}+1+1}{\sqrt{x}+1}=1+\dfrac{1}{\sqrt{x}+1}>=1>0\)

=>A>|A|

Answer 2

Ta có: A= \(\dfrac{\sqrt{x}+2}{\sqrt{x}+1}\)= \(1+\dfrac{1}{\sqrt{x}+1}\)

Vì x ≥0⇒\(\sqrt{x}\) ≥0⇒\(\sqrt{x}+1 \)≥ 1 ⇒ \(1+\dfrac{1}{\sqrt{x}+1}\)≥ 2

hay A≥ 2>0

Khi đó ta có: A=|A|

Vậy A=|A|