Question

giúp mình câu 33 với

Answer 1

33: \(=\dfrac{\left(\sqrt{5}+\sqrt{6}\right)^2-\left(\sqrt{5}-\sqrt{6}\right)^2}{5-6}\)

\(=\dfrac{11+2\sqrt{30}-11+2\sqrt{30}}{-1}=-4\sqrt{30}\)

Answer 2

Answer 3

Lời giải:
\(=\frac{\sqrt{5}+\sqrt{6}}{\sqrt{5}-\sqrt{6}}-\frac{\sqrt{5}-\sqrt{6}}{\sqrt{6}+\sqrt{5}}=\frac{(\sqrt{5}+\sqrt{6})^2-(\sqrt{5}-\sqrt{6})^2}{(\sqrt{5}-\sqrt{6})(\sqrt{6}+\sqrt{5})}\)

\(=\frac{4\sqrt{30}}{5-6}=-4\sqrt{30}\)