Question

giúp mình càng nhanh càng tốt nhé các bạn tìm x biết : a' ( x - 2 ) . 13 = 0 b' (x - 2 ) .13 = 13 c' (x - 2 ) : 13 = 1 d' 13: (x - 2 ) = 1 e' 13 : (x -2) = 13

Answer 1

\(a,\left(x-2\right)\cdot13=0\\ \Rightarrow x-2=0\\ \Rightarrow x=2\)

Vậy x = 2

\(b,\left(x-2\right)\cdot13=13\\ \Rightarrow x-2=1\\ \Rightarrow x=3\)

Vậy x = 3

\(c,\left(x-2\right):13=1\\ \Rightarrow x-2=13\\ \Rightarrow x=15\)

Vậy x = 15

\(d,13:\left(x-2\right)=1\\ \Rightarrow x-2=13\\ \Rightarrow x=15\)

Vậy x = 15

\(e,13:\left(x-2\right)=13\\ \Rightarrow x-2=1\\ \Rightarrow x=3\)

Vậy x = 3

Answer 2

Vậy x = 2

Vậy x = 3

Vậy x = 15

Vậy x = 15

Vậy x = 3

Answer 3

a) \(\left(x-2\right).13=0\)

=> \(\left(x-2\right)=0:13\)

=> \(x-2=0\)

=> \(x=0+2\)

=> \(x=2\)

Vậy \(x=2.\)

b) \(\left(x-2\right).13=13\)

=> \(\left(x-2\right)=13:13\)

=> \(x-2=1\)

=> \(x=1+2\)

=> \(x=3\)

Vậy \(x=3.\)

c) \(\left(x-2\right):13=1\)

=> \(\left(x-2\right)=1.13\)

=> \(x-2=13\)

=> \(x=13+2\)

=> \(x=15\)

Vậy \(x=15.\)

d) \(13:\left(x-2\right)=1\)

=> \(\left(x-2\right)=13:1\)

=> \(x-2=13\)

=> \(x=13+2\)

=> \(x=15\)

Vậy \(x=15.\)

e) \(13:\left(x-2\right)=13\)

=> \(\left(x-2\right)=13:13\)

=> \(x-2=1\)

=> \(x=1+2\)

=> \(x=3\)

Vậy \(x=3.\)

Chúc bạn học tốt!