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giúp mik bài 4 vs

Nguyễn Lê Phước Thịnh
16 tháng 11 2023 lúc 17:41

Bài 4:

a: \(\sqrt{6^2+8^2}-3\sqrt{25}\)

\(=\sqrt{36+64}-3\cdot5\)

\(=\sqrt{100}-15=10-15=-5\)

b: \(\left(-5\dfrac{1}{2}\right)\left(-\dfrac{1}{2}\right)-\sqrt{\dfrac{4}{3^2}}\cdot\left(-\dfrac{2}{3}\right)\)

\(=\left(-\dfrac{11}{2}\right)\left(-\dfrac{1}{2}\right)-\dfrac{2}{3}\cdot\left(-\dfrac{2}{3}\right)\)

\(=\dfrac{11}{4}+\dfrac{4}{9}=\dfrac{99+16}{36}=\dfrac{115}{36}\)

c: \(\sqrt{16}\cdot\sqrt{4}-\sqrt{25}+2\sqrt{49}\)

\(=4\cdot2-5+2\cdot7\)
\(=8-5+14=22-5=17\)

d: \(\dfrac{1}{\sqrt{36}}+\dfrac{\sqrt{25}}{6}-\sqrt{0,81}\)

\(=\dfrac{1}{6}+\dfrac{5}{6}-0,9\)

=1-0,9

=0,1

e: \(-\dfrac{\sqrt{9}}{16}+\dfrac{5}{\sqrt{36}}\)

\(=-\dfrac{3}{16}+\dfrac{5}{6}\)

\(=\dfrac{-9+40}{48}=\dfrac{31}{48}\)

f: \(\dfrac{\sqrt{9}}{8}\cdot\dfrac{16}{\sqrt{225}}-\dfrac{3}{4\sqrt{4}}\cdot\dfrac{2}{5\sqrt{3^2}}\)

\(=\dfrac{3}{8}\cdot\dfrac{16}{15}-\dfrac{3}{4\cdot2}\cdot\dfrac{2}{5\cdot3}\)

\(=\dfrac{3}{15}\cdot\dfrac{16}{8}-\dfrac{1}{20}\)

\(=\dfrac{1}{5}\cdot2-\dfrac{1}{20}=\dfrac{2}{5}-\dfrac{1}{20}=\dfrac{7}{20}\)

Phong
16 tháng 11 2023 lúc 17:45

Bài 4:

a) \(\sqrt{6^2+8^2}-3\sqrt{25}\)

\(=\sqrt{36+64}-3\cdot5\)

\(=\sqrt{100}-15\)

\(=10-15\)

\(=-5\)

b) \(\left(-5\dfrac{1}{2}\right)\cdot\left(-\dfrac{1}{2}\right)-\sqrt{\dfrac{4}{3^2}}\cdot\left(-\dfrac{2}{3}\right)\)

\(=\left(-\dfrac{11}{2}\right)\cdot\left(-\dfrac{1}{2}\right)-\dfrac{\sqrt{4}}{\sqrt{3^2}}\cdot\left(-\dfrac{2}{3}\right)\)

\(=\dfrac{11}{4}-\dfrac{2}{3}\cdot\left(-\dfrac{2}{3}\right)\)

\(=\dfrac{11}{4}+\dfrac{4}{9}\)

\(=\dfrac{115}{36}\)

c) \(\sqrt{16}\cdot\sqrt{4}-\sqrt{25}+2\sqrt{49}\)

\(=4\cdot2-5+2\cdot7\)

\(=8-5+14\)

\(=17\)

d) \(\dfrac{1}{\sqrt{36}}+\dfrac{\sqrt{25}}{6}-\sqrt{0,81}\)

\(=\dfrac{1}{6}+\dfrac{5}{6}-0,9\)

\(=1-0,9\)

\(=0,1\)

e) \(-\dfrac{\sqrt{9}}{16}+\dfrac{5}{\sqrt{36}}\)

\(=-\dfrac{3}{16}+\dfrac{5}{6}\)

\(=\dfrac{31}{48}\)

f) \(\dfrac{\sqrt{9}}{8}\cdot\dfrac{16}{\sqrt{225}}-\dfrac{3}{4\sqrt{4}}\cdot\dfrac{2}{5\cdot\sqrt{3^2}}\)

\(=\dfrac{3}{8}\cdot\dfrac{16}{15}-\dfrac{3}{4\cdot2}\cdot\dfrac{2}{5\cdot3}\)

\(=\dfrac{3\cdot16}{8\cdot15}-\dfrac{3\cdot2}{4\cdot2\cdot5\cdot3}\)

\(=\dfrac{2}{5}-\dfrac{1}{20}\)

\(=\dfrac{7}{20}\)

Phong
16 tháng 11 2023 lúc 17:54

a) \(2,4-3x\cdot0,5=0,9\)

\(\Rightarrow3x\cdot0,5=2,4-0,9\)

\(\Rightarrow3x\cdot0,5=0,5\)

\(\Rightarrow3x=1\)

\(\Rightarrow x=\dfrac{1}{3}\)

b) \(\left|8,8x-50\right|:0,4=51\)

\(\Rightarrow\left|8,8x-50\right|=20,4\)

TH1: \(8,8x-50=20,4\Rightarrow8,8x=70,4\Rightarrow x=8\)

TH2: \(8,8x-50=-20,4\Rightarrow8,8x=29,6\Rightarrow x=\dfrac{37}{11}\)

c) \(\left|\dfrac{3}{4}x-\dfrac{3}{4}\right|=\left|-\dfrac{3}{4}\right|\)

\(\Rightarrow\dfrac{3}{4}\left|x-1\right|=\dfrac{3}{4}\)

\(\Rightarrow\left|x-1\right|=1\)

TH1: \(x-1=1\Rightarrow x=2\)

TH2: \(x-1=-1\Rightarrow x=0\) 

d) \(\left(3x-4\right)^2=\left(-\dfrac{3}{4}\right)^2\)

TH1: \(3x-4=-\dfrac{3}{4}\)

\(\Rightarrow3x=\dfrac{13}{4}\Rightarrow x=\dfrac{13}{12}\)

TH2: \(3x-4=\dfrac{3}{4}\)

\(\Rightarrow3x=\dfrac{19}{4}\Rightarrow x=\dfrac{19}{12}\)

e) \(\left(\dfrac{1}{3}\right)^{2x-1}=3^5\)

\(\Rightarrow\left(\dfrac{1}{3}\right)^{2x-1}=\left[\left(\dfrac{1}{3}\right)^{-1}\right]^5\)

\(\Rightarrow\left(\dfrac{1}{3}\right)^{2x-1}=\left(\dfrac{1}{3}\right)^{-5}\)

\(\Rightarrow2x-1=-5\)

\(\Rightarrow2x=-4\)

\(\Rightarrow x=-2\) 

f) \(\left|5-3x\right|+\dfrac{2}{3}=\dfrac{1}{6}\)

\(\Rightarrow\left|5-3x\right|=-\dfrac{1}{2}\)

TH1: \(5-3x=-\dfrac{1}{2}\Rightarrow3x=\dfrac{11}{2}\Rightarrow x=\dfrac{11}{6}\)

TH2: \(5-3x=\dfrac{1}{2}\Rightarrow3x=\dfrac{9}{2}\Rightarrow x=\dfrac{3}{2}\)


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