Question

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Answer 1

Bài 1:

\(a,=\dfrac{3x-3+4x+2+1-5x}{6x}=\dfrac{2x}{6x}=\dfrac{1}{3}\\ b,=\dfrac{x+y+2x-2y-3}{\left(x-y\right)\left(x+y\right)}=\dfrac{3x-y-3}{\left(x-y\right)\left(x+y\right)}\\ c,=\dfrac{4x-8-3x-6+12}{\left(x-2\right)\left(x+2\right)}=\dfrac{x-2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x+2}\)

Bài 2:

\(a,A=\dfrac{x-1+x^2+2}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{1}{x-1}=\dfrac{1}{11-1}=\dfrac{1}{10}\\ b,B=\dfrac{x^2+2x+1-x^2-2x}{x\left(x-1\right)\left(x+1\right)}=\dfrac{1}{x\left(x^2-1\right)}=\dfrac{1}{\left(-\dfrac{1}{3}\right)\left(\dfrac{1}{9}-1\right)}=\dfrac{27}{8}\)

Bài 3:

\(a,=\dfrac{1}{x}-\dfrac{1}{x+1}+\dfrac{1}{x+1}-\dfrac{1}{x+2}+\dfrac{1}{x+2}-\dfrac{1}{3+x}+\dfrac{1}{x+3}=\dfrac{1}{x}\)