Question

Giúp em

Answer 1

Câu 2: 

Theo đề, ta có:

\(\left\{{}\begin{matrix}-2\cdot3^2+b\cdot3+c=-5\\-\dfrac{b}{2\cdot\left(-2\right)}=\dfrac{3}{2}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3b+c=13\\b=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}c=-5\\b=6\end{matrix}\right.\)