d) Ta có: \(1,25\cdot\left(-2\right)^2-0.5:\dfrac{5}{12}+15\%\)
\(=\dfrac{5}{4}\cdot4-\dfrac{1}{2}\cdot\dfrac{12}{5}+\dfrac{3}{20}\)
\(=5-\dfrac{6}{5}+\dfrac{3}{20}\)
\(=\dfrac{100}{20}-\dfrac{120}{20}+\dfrac{3}{20}\)
\(=\dfrac{-17}{20}\)
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