a) \(\left(2x-1\right)\left(x^2-x+1\right)+x^2\left(3-2x\right)=2\)
\(\Rightarrow2x^3-2x^2+2x-x^2+x-1+3x^2-2x^3=2\)
\(\Rightarrow\left(2x^3-2x^3\right)-\left(2x^2+x^2-3x^2\right)+\left(2x+x\right)-1=2\)
\(\Rightarrow3x-1=2\)
\(\Rightarrow3x=2-1\)
\(\Rightarrow3x=1\)
\(\Rightarrow x=\dfrac{1}{3}\)
b: =>\(3\left(x-2-4x^2+8x\right)+4\left(3x^2+7x+2\right)=24\)
=>-12x^2+27x-6+12x^2+28x+8=24
=>55x+2=24
=>55x=22
=>x=2/5
c: \(\Leftrightarrow\left(x^2+3x+2\right)\left(x+3\right)-x^3-8x^2-16x-6=0\)
=>\(x^3+6x^2+11x+6-x^3-8x^2-16x-6=0\)
=>\(-2x^2-5x=0\)
=>x=0 hoặc x=-5/2
d: \(\Leftrightarrow x^3+2x^2+4x+x^2+2x+4-x^3-3x^2+8=0\)
=>6x+12=0
=>x=-2