Question

Giải pt, ko sử dụng mt cầm tay
\(\dfrac{\sqrt{x}+1}{\sqrt{x}+3}\)=\(\dfrac{1}{2}\)

Answer 1

\(\Leftrightarrow2\sqrt{x}+2=\sqrt{x}+3\)

=>\(\sqrt{x}=1\)

hay x=1

Answer 2

\(\dfrac{\sqrt{x+1}}{\sqrt{x+3}}=\dfrac{1}{2}\)

\(\Leftrightarrow2\left(\sqrt{x+1}\right)=\sqrt{x}+3\)

\(\Leftrightarrow2\sqrt{x}+2=\sqrt{x}+3\)

\(\Leftrightarrow2\sqrt{x}+2-\sqrt{x}-3=0\)

\(\Leftrightarrow\sqrt{x}-1=0\Leftrightarrow\sqrt{x}=1\Leftrightarrow x=1\)

Answer 3

\(\dfrac{\sqrt{x}+1}{\sqrt{x}+3}=\dfrac{1}{2}\)

=> \(2\left(\sqrt{x}+1\right)=\sqrt{x}+3\)

     \(2\sqrt{x}+2=\sqrt{x}+3\)

     \(2\sqrt{x}-\sqrt{x}=3-2\)

     \(\sqrt{x}=1\)

=> x=1