\(\dfrac{\left|x-1\right|+x+5}{2x-6}=1\) ĐK: x khác 3
\(pt\Leftrightarrow\left|x-1\right|=x-11\)
+) Với x ≥ 1 có:
x - 1 = x - 11 <=> 0x = -10 (vô lí)
+) Với x < 1 có:
x-1 = 11 - x
<=> 2x = 12 <=> x = 6 (ktm)
Vậy pt vô nghiệm
giải hệ pt:
(1) \(\left\{{}\begin{matrix}x^2-3xy+2y^2=0\\3x+y=6\end{matrix}\right.\)
(2)\(\left\{{}\begin{matrix}\dfrac{x-1}{2x+1}-\dfrac{y-2}{y+2}=1\\\dfrac{3x-3}{2x+1}+\dfrac{2y-4}{y+2}=3\end{matrix}\right.\)
(3)\(\left\{{}\begin{matrix}2\left(x+y\right)+\sqrt{x+1}=4\\x+y-3\sqrt{x+1}=-5\end{matrix}\right.\)
1.Giải pt \(\dfrac{1}{\left(2x+1\right)^2}+\dfrac{1}{\left(2x+2\right)^2}=3\)
2.Tìm nghiệm nguyên của pt x3+y3-x2y-xy2=5
Giải hệ pt:
\(\left\{{}\begin{matrix}x^3+y^3+3xy=1\\\sqrt{\left(4-x\right)\left(13-y\right)}=\dfrac{2x+2y+25}{2x+y+2}\end{matrix}\right.\)
mog mn giúp mk cần gấp
giải pt
\(\dfrac{2x+1}{x-1}\)= \(\dfrac{5\left(x-1\right)}{x+1}\)
Giải hệ PT \(\left\{{}\begin{matrix}\dfrac{x}{y}+2.\dfrac{y}{x}=3\\2x^2-3y=-1\end{matrix}\right.\)
giải pt
\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{5}{6}\\\dfrac{\dfrac{2}{3}}{x}+\dfrac{\dfrac{2}{3}}{y}+\dfrac{\dfrac{8}{9}}{y}=1\end{matrix}\right.\)
giúp mình giải chi tiết với nha đừng làm tắt ok thanks
Giải phương trình:
1, \(\left(x^2+x+1\right)\left(x^4+2x^3+7x^2+26x+37\right)=5\left(x+3\right)^3\)
2, \(\left(x+1\right)^3+\left(x+3\right)^3+6\left(x+1\right)\left(x+7\right)\left(x+3\right)=8\left(x+2\right)^3\)
3, \(x^3+\left(x-1\right)^3+3x\left(x-1\right)\left(x^4+x\right)=\left(2x-1\right)^3\)
4, \(\dfrac{\left(x+1\right)^3}{3x+1}+\dfrac{x^3+5x+2}{x^3+2x+1}=x+3\)
5, \(\dfrac{5x^3+x^2+x+1}{4x^2+1}+\dfrac{6\left(4x^2+1\right)}{x^3+x^2+1}=x+7\)
6, \(\left(x^2-4x+1\right)^3+\left(8x-x^2+4\right)^3+\left(x-5\right)^3=125x^3\)
Giải phương trình:
1, \(\left(x+3\right)\left(3x^4+8x^2+12x+21\right)=5\left(x^2+1\right)^3\)
2, \(3\left(x^2+2x-1\right)^2-2\left(x^2+3x-1\right)^2+5x^2=0\)
3, \(\dfrac{x^2+x+1}{x+1}+\dfrac{x^2+2x+2}{x+2}-\dfrac{x^2+3x+3}{x+3}-\dfrac{x^2+4x+4}{x+4}=0\)
4, \(\left(\dfrac{x+6}{x-6}\right)\left(\dfrac{x+4}{x-4}\right)^2+\left(\dfrac{x-6}{x+6}\right)\left(\dfrac{x+9}{x-9}\right)^2=2.\dfrac{x^2+36}{x^2-36}\)
giải pt
a) \(\dfrac{2x^3-3x-10}{\left(2-x\right)^3}=-2\)
b) \(\left(x^2-2x\right)^2-2\left(x-1\right)^2-1=0\)
