\(x\ge5\)
\(C_x^4+C_x^4=3.C_{x+1}^6\)
\(\frac{x!.2}{4!\left(x-4\right)!}=\frac{3.\left(x+1\right)!}{\left(x-5\right)!.6!}\)
\(\Leftrightarrow\frac{2}{x-4}=\frac{3\left(x+1\right)}{30}\)
\(\Leftrightarrow\left(x-2\right)\left(x+1\right)=20\)
\(\Leftrightarrow x^2-x-22=0\)
Pt ko có nghiệm nguyên nên đề bài sai