ĐKXĐ: \(x\ge-\dfrac{1}{4}\)
\(\Leftrightarrow4x^2+4x+2=2\sqrt{4x+1}\)
\(\Leftrightarrow4x^2+\left(4x+1-2\sqrt{4x+1}+1\right)=0\)
\(\Leftrightarrow\left(2x\right)^2+\left(\sqrt{4x+1}-1\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x=0\\\sqrt{4x+1}-1=0\end{matrix}\right.\) \(\Leftrightarrow x=0\)