ĐK:....
\(x^2+9x+20=2\sqrt{3x+10}\)
\(\Leftrightarrow x^2+9x+20-2\sqrt{3x+10}=0\)
\(\Leftrightarrow x^2+6x+9+3x+10-2\sqrt{3x+10}+1=0\)
\(\Leftrightarrow\left(x+3\right)^2+\left(\sqrt{3x+10}-1\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+3=0\\\sqrt{3x+10}=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-3\\3x+10=1\end{matrix}\right.\)
\(\Leftrightarrow x=-3\)
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