ĐKXĐ: \(x\ge1\)
\(pt\Leftrightarrow x-1+2x-1+2\sqrt{\left(x-1\right)\left(2x-1\right)}=25\)
\(\Leftrightarrow2\sqrt{2x^2-3x+1}=27-3x\)
\(\Leftrightarrow\left\{{}\begin{matrix}27-3x\ge0\\4\left(2x^2-3x+1\right)=\left(27-3x\right)^2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\le9\\x^2-150x+725=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\le9\\\left(x-145\right)\left(x-5\right)=0\end{matrix}\right.\Leftrightarrow x=5\left(tm\right)\)