Đặt \(\left\{{}\begin{matrix}\sqrt[3]{x+1}=a\\\sqrt[3]{x-1}=b\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}a^2+b^2+ab=1\\a^3-b^3=2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}a^2+b^2+ab=1\\\left(a-b\right)\left(a^2+b^2+ab\right)=2\end{matrix}\right.\)
\(\Rightarrow a-b=2\Rightarrow a^3-b^3-3ab\left(a-b\right)=8\)
\(\Leftrightarrow2-6ab=8\Leftrightarrow ab=1\)
\(\Leftrightarrow\left(x-1\right)\left(x+1\right)=1\Leftrightarrow x=\pm\sqrt{2}\)