\(\sqrt{16x+16}+\sqrt{9x+9}-\sqrt{25x+25}+2\sqrt{x+1}=8\)
\(\Rightarrow4\sqrt{x+1}+3\sqrt{x+1}-5\sqrt{x+1}+2\sqrt{x+1}=8\)
\(\Rightarrow\sqrt{x+1}\left(4+3-5+2\right)=8\)
\(\Rightarrow4\sqrt{x+1}=8\)
\(\Rightarrow\sqrt{x+1}=2\)
\(\Rightarrow x+1=4\)
\(\Rightarrow\)\(x=3\)
\(\sqrt{16x+16}\) + \(\sqrt{9x+9}\) - \(\sqrt{25x+25}\) + 2\(\sqrt{x+1}\) = 8 ( x\(\ge\) -1)
<=> 4\(\sqrt{x+1}\) + 3\(\sqrt{x+1}\) - 5\(\sqrt{x+1}\) + 2\(\sqrt{x+1}\) = 8
<=> 4\(\sqrt{x+1}\) = 8
<=> \(\sqrt{x+1}\) = 2
<=> x + 1 =4
<=> x=3 (TM)
ta có:
\(\sqrt{16x+16}+\sqrt{9x+9}-\sqrt{25x+25}+2\sqrt{x+1}=8\)
=> \(4\cdot\sqrt{x+1}+3\sqrt{x+1}-5\sqrt{x+1}+2\sqrt{x+1}=8\)
=>\(\sqrt{x+1}\cdot\left(4+3-5+2\right)=8\)
=>\(4\sqrt{x+1}=8\)
=> \(\sqrt{x+1}=2\)
=>x+1=3
=> x=2
chết mk nhầm rùi đáng lẽ kq phải là 3 cơ mk sai rùi bn thông cảm nha
